FM radio bands range from 88 MHZ through
108 MHz.
The speed of light is 3 × 108 m/s.
a)What is the wavelength for the FM radio
band at 96 MHz?
Answer in units of m
b)What is the wavelength for the FMradio band
at 107 MHz?
Answer in units of m
108 MHz.
The speed of light is 3 × 108 m/s.
a)What is the wavelength for the FM radio
band at 96 MHz?
Answer in units of m
b)What is the wavelength for the FMradio band
at 107 MHz?
Answer in units of m
-
Let me show you the normal way to show exponents here.
The speed of light is 3 × 10^8 m/s
where the ^ is shift+6. (Another way: 3E8 m/s.)
a) The formula that relates frequency, wavelength and speed of light is
c = lambda*f
Note the units. c has units of m/s, lambda has units of m, and frequency has units of Hz, which 50 years ago was called cycles/second. A cycle isn't really a unit, so frequency has units of s^-1. So do you see that the result of multiplying lambda by f would give you a result in units of m/s? That should help you remember without actually memorizing.
So if you want lambda, do the algebra to get lambda = c/f
You have a speed of 3 × 10^8 m/s and a frequency of 96 MHz or 96 x 10^6 Hz. Now, do the arithmetic.
b) Same as above.
The speed of light is 3 × 10^8 m/s
where the ^ is shift+6. (Another way: 3E8 m/s.)
a) The formula that relates frequency, wavelength and speed of light is
c = lambda*f
Note the units. c has units of m/s, lambda has units of m, and frequency has units of Hz, which 50 years ago was called cycles/second. A cycle isn't really a unit, so frequency has units of s^-1. So do you see that the result of multiplying lambda by f would give you a result in units of m/s? That should help you remember without actually memorizing.
So if you want lambda, do the algebra to get lambda = c/f
You have a speed of 3 × 10^8 m/s and a frequency of 96 MHz or 96 x 10^6 Hz. Now, do the arithmetic.
b) Same as above.