Algebra II Problem. Help
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Algebra II Problem. Help

[From: ] [author: ] [Date: 12-05-09] [Hit: ]
it doesnt apply to this specific problem, but whenever you multiply or divide both sides of an inequality by a negative number, you must flip the sign. For example,......
I forgot how to get the y alone, so.... SHOW me how to get this inequality alone.
2y - x > -6

-
2y - x > -6

Add x to both sides:
2y-x+x > -6+x
2y > -6+x
2y > x-6

Divide both sides by 2:
2y/2 > (x-6)/2
y > (1/2)x-3

Answer: y > (1/2)x-3
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By the way, it doesn't apply to this specific problem, but whenever you multiply or divide both sides of an inequality by a negative number, you must flip the sign. For example, -5y > x-10:
-5y > x-10
-5y/-5 > (x-10)/-5
y < (-1/5)x+2

-
2y - x > -6
+ x + x
2y > x - 6
/2 /2 /2
y > (1/2)x - 3

-
2y - x > -6
2y >x -6
y >x/2 - 3

-
2y - x > -6
2y > x+6
y > x/2 + 6
1
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