Find the solution of: x=16/2+2*5

1) Evaluate: -1.8-3.2+2.4
2) Evaluate: -48/(-12)
3) Write the equation in slope-intercept form of the line passing through each pair of points: (-8,2) and (0,6)
4) Determine the y-intercept of the graph: -3x-5y=15
5) Determine the slope and y-intercept of the graph: -x+2y=4
6) Write an equation in slope-intercept form of a line with the following characteristics. Perpendicular to the graph of: y=3/2*-3 with a y-intercept of 5.
7) Write an equation in slope-intercept form of a line with the following characteristics: parallel to the graph of: -4x+3y=12 and passes through the origin.
Thanks!

18
1. -2.6
2. 4
3. m = (2 - 6)/(-8 - 0) = -4/-8 = 1/2
.....y = mx + b
.....2 = (1/2)(-8) + b
.....2 = -4 + b
.....6 = b
.....y = (x/2) + 6
4. -5y = 3x + 15
.....y = (-3x/5) - 3
.....y-inter = -3
5. 2y = x + 4
.....y = (x/2) + 2
.....m = 1/2, b = 2
6. y = (3x/2) - 3, m = 3/2, perpendicular m = -2/3
.....y = (-2x/3) + 5
7. 3y = 4x + 12
.....y = (4x/3) + 4
.....y = 4x/3

x = 16/2 + 2*5
x = 16/2 + 40
x = 8 + 40
x = 48.