point slope and slope intercept form?
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Firstly convert 3x - 2y = 5 to the slope intercept form:
2y = 3x - 5
y = (3/2)x - 5/2
the slope is 3/2 and this will be the slope of the new line that is parallel to this one:
y = (3/2)x + b
we know that y = 1 when x = -3, so
1 = (3/2)*-3 + b
b = 1 + 9/2 = 11/2
so the parallel line's formula is
y = (3/2)x + 11/2
2y = 3x - 5
y = (3/2)x - 5/2
the slope is 3/2 and this will be the slope of the new line that is parallel to this one:
y = (3/2)x + b
we know that y = 1 when x = -3, so
1 = (3/2)*-3 + b
b = 1 + 9/2 = 11/2
so the parallel line's formula is
y = (3/2)x + 11/2
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SI. y=(3/2)x+(11/2) PS. y-(11/2)=(3/2)(x-0)