I've been stuck on these two problems for a while now...
Using the word "ADJUSTING"
A: How many of these nine-letter arrangements have a consonant in the 5th position and a J in the 6th?
B: How many different 9 letter arrangements can be made?
C: If a nine-letter arrangement is selected at random, what is the probability that a consonant is 5th and J is 6th?
Thanks!
Using the word "ADJUSTING"
A: How many of these nine-letter arrangements have a consonant in the 5th position and a J in the 6th?
B: How many different 9 letter arrangements can be made?
C: If a nine-letter arrangement is selected at random, what is the probability that a consonant is 5th and J is 6th?
Thanks!
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A) we have 1 options to put J in 6th position.... and 5 options to put a consonant in the 5th position...
and after putting J in 6th and a consonant in 5th... there are 7 letters for the other positions...
Then the result is: 1*5*7! = 5(1*2*3*4*5*6*7). OK!
B) Without restrictions... the the total is 9! = 1*2*3*4*5*6*7*8*9 OK!
C) To find the probability just divide the total 9! by 5*7! Then it is 9*8/5 OK
and after putting J in 6th and a consonant in 5th... there are 7 letters for the other positions...
Then the result is: 1*5*7! = 5(1*2*3*4*5*6*7). OK!
B) Without restrictions... the the total is 9! = 1*2*3*4*5*6*7*8*9 OK!
C) To find the probability just divide the total 9! by 5*7! Then it is 9*8/5 OK
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V.: A, U, I
C.: D, J, S, T, N, G
A) 5th position: 6C1, 6th positive: 1. Other positions: 7!
Answer: 6*7!
B) 9!
C) 6/9!
C.: D, J, S, T, N, G
A) 5th position: 6C1, 6th positive: 1. Other positions: 7!
Answer: 6*7!
B) 9!
C) 6/9!