Algebra 2 help easy 10 points ? Solve all Radical Equations

1. √x + 6 = x

2. √x + 4 = √ x - 1 + 1

Assuming √x + 6 = x means √(x + 6) = x

Square both sides x+6 = x^2

x^2 - x - 6 = 0

(x-3)(x+2) so x = 3 or -2

2) √(x + 4) = √( x - 1) + 1

Square both sides

x+4 = x-1 + 1 +2(√( x - 1))

Simplify

4 = 2(√( x - 1))

2 =√( x - 1)

4 = x - 1

x= 5

√x + 6 = x ====> x- √x -6=0 ===> (√x +2)(√x -3) =0 ===>√x =2 ==>x=4
or √x =3 ===>x=9

√x + 4 = √ x - 1 + 1=====> √x + 4 -√ x +1 - 1=0

4=0

no solution

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1. x=9
2. The square root plus four cannot equal the square root.