Differential Equation, HELP
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Differential Equation, HELP

[From: ] [author: ] [Date: 12-05-29] [Hit: ]
k=-.02 and it is right but I dont know how to do part b]-dQ/dt = -.dQ/dt = Ck*e^(kt) = -0.k = -0.......
Suppose Q=Ce^kt satisfies the differential equation dQ/dt = -0.02Q
What (if anything) does this tell you about the values of C and k?

a) Either: C= , and k=
(For each of C and k, enter the value that the parameter must take, or enter the word "anything" if there are no restrictions on the value.)
[I got C=anything, k=-.02 and it is right]

b) or: C= , and k=
(For each of C and k, enter the value that the parameter must take, or enter the word anything if there are no restrictions on the value.)

[I got a) C=anything, k=-.02 and it is right but I don't know how to do part b]

-
dQ/dt = -.02Q

dQ/dt = Ck*e^(kt) = -0.02C*e^(kt)

k = -0.02
1
keywords: HELP,Differential,Equation,Differential Equation, HELP
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