Find dy if y = (3x^2 + 1)^2/3

dy = 2/3*(3x^2 + 1)^-1/3 * d (3x^2 + 1)
. . .= 2 / 3(3x^2 + 1)^1/3 * 6x dx
. .= 4x dx / (3x^2 + 1)^1/3 . .answer

4x
__________
(3x^2+1)^1/3

im sorry this is way to hard to explain over the internet, i tried. But i hope the right answer can help you figure it out.