Can someone explain how to get the integral of 1/(x^(2)+25) is
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Can someone explain how to get the integral of 1/(x^(2)+25) is

[From: ] [author: ] [Date: 12-06-14] [Hit: ]
......
please show the steps especially when you use arctan.
the answer is suppose to be 10(1/5*tan^-1*x/5)

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∫dx/(x² + 25) = 1/25*∫dx/(x²/25 + 1)

u = x/5

5 du = dx

1/5*∫du/(u² + 1) = 1/5*arctan(u) + C

= 1/5*arctan(x/5) + C
1
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