Stats question !! how did they get this answer??HELP!
Favorites|Homepage
Subscriptions | sitemap
HOME > > Stats question !! how did they get this answer??HELP!

Stats question !! how did they get this answer??HELP!

[From: ] [author: ] [Date: 12-06-14] [Hit: ]
444, μ = 0 under our null hypothesis, s_d = 2.698, n = 9 (x_bar and s_d obtained using calc). Then T = 2.......
So im trying to figure out how this person got this answer. i keep doing it and am getting different answers, Then again i dont really know what im doing.

I get this: ( how to fid the test statistic value)
x_bar is approx. 2.444, μ = 0 under our null hypothesis, s_d = 2.698, n = 9 (x_bar and s_d obtained using calc). Then T = 2.444 / (2.698 / sqrt(9)) = 3 * 2.444 / 2.698 = 2.718

but its here, where they ask the P-value, like in this example i do not understand where the 3.415 is coming from, and what they did to get it and the 0.013.

b) The test statistic p-value is P(T > 3.415) where T is a t-distributed random variable with 8 degrees of freedom (just larger than 3.415 because it's a one-sided test). Using a calc we get p = 0.013.


THANKS SO MUCH !

-
You have provided the value
_
x = 2.444 and s(sample standard deviation) = 2.698
and n{sample size} = 9

Now any T or z is calculated

using

.......x - µ
z = ▬▬▬
.........σ

T is calculated with the estimators

......._
.......x - {hypothesized µ}
T = ▬▬▬
.........s {of xbar}

but of course, hypothesized µ = 0 so that is why you
get your

2.44
▬▬▬▬ = 2.717568569
2.698/√9

For a small sample, it has a
students T distribution with 8 degrees of freedom

and I am not sure what resourses you are using
to evaluate T. I studied statistics in the 1970's and
1980's when we had to refer to T tables in the backs of
stats books. Now, there are online calculators such as
the one I linked in the source.

Using that calculator, I determine that

Pr(T< 2.717568569) with 8 degrees of freedom is

0.9868

It turns out that the P value is actually
Pr(T>2.71568569) and that is 1-0.9868 and that
calculates to be 0.0132

Now your part b Test statistic is suggested at 3.415 and
its p value is P(T > 3.415)

That number calculates as 0.004584405
which is less than 1/2 of 1%.

-
but i am still slightly confused, i looked up 2.718 in the z table and found it to be .9966 and 1-.9966 = 0.0034

Report Abuse


-
and when i look up 3.14 in the z table i get .9997 , 1-.9997= 0.0003.
i figured maybe im lloking in the wrong table so i tried the t table but just by looking at the table it cant be it.
online calc is very useful but wont have during exam !!
what am i not seeing !!! :)

Report Abuse

1
keywords: HELP,get,answer,did,this,they,Stats,question,how,Stats question !! how did they get this answer??HELP!
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .