Equation: Log²(x)Log²(x/16) = Log²(x/64)
Beginning of the solution:
Log²(x)Log²(x/16) = Log²(x)*(Log²(x) - Log²(16)) = Log²(x) - Log²(64) by the log-division rule
Huh? I didn't understand a thing! Could you explain step by step what did they do?
Beginning of the solution:
Log²(x)Log²(x/16) = Log²(x)*(Log²(x) - Log²(16)) = Log²(x) - Log²(64) by the log-division rule
Huh? I didn't understand a thing! Could you explain step by step what did they do?
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Log (a/b) = log a - log b
...suffices to explain it.
I assume that Log²(x) means "log (to the base 2) of x" rather than "log x * log x"...there seems to be no universally accepted short way of writing "log (to the base a) of b"
...suffices to explain it.
I assume that Log²(x) means "log (to the base 2) of x" rather than "log x * log x"...there seems to be no universally accepted short way of writing "log (to the base a) of b"
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Two real solutions, two non-real solutions.