Integral of (1/x^2) - 1/x help keep getting wrong answer

integral of (1/x^2) - 1/x

so i get -1/x - lnx

where x=2
so i get -1/2 -ln2

but its wrong i dont know how they are getting

-1/2 +ln2

any help thanks 10 points

I think you're answer's right, theirs must be a typo.

Hope this helps.