How do you solve x^4 - 4x^2 + 3 = 0

factor it.

(x^2 - 3)(x^2 - 1) = 0

Use zero property law:
(x^2 - 3) = 0
x = ±√3

(x^2 - 1) = 0
x = ± 1

let w = x^2

x^4 - 4x^2 + 3 = 0 becomes

w^2 - 4w + 3 = 0 --> when you are done factoring, replace w with x^2 and see if you can factor it further

Let x^2 = u
u^2 - 4u + 3 = 0
(u - 1)(u - 3) = 0
u = 1, 3

x^2 = 1, 3
x = -1, 1, -√3, √3

given.that

x^4 - 4x^2 + 3 = 0

or.(x^2 - 3) = 0
or.x = ±√3 ans.