How do you solve for this absolute value

3abs(x+1)−4=− 2

3|x+1|-4=-2
3|x+1| = 4-2
3|x+1| = 2
|x+1| = 2/3
±(x+1) = 2/3
x+1 = ±2/3
x = -1 ± 2/3
x = -3/3 ± 2/3
x = (-3 ± 2)/3
x = -1/3 or -5/3