Having difficulty trying to understand what this question is telling me to do

In Exercises 1-8, given y=f(u) and u=g(x), find dy/dx = f'(g(x))g'(x).

1. y = 6u - 9, u = (1/2)x^4

I know that I am going to use the chain rule, but I don't know how to set it up. Is it supposed to be 6[(1/2)x^4] - 9?

Yes.

y' = (dy/du)(du/dx) is probably more familiar to you