What is the magnitude of the magnetic flux through the coil
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What is the magnitude of the magnetic flux through the coil

[From: ] [author: ] [Date: 11-04-24] [Hit: ]
us/i/p022figure.png/-The flux is NBA*sin(25.8) = 38*5.37*π*0.321^2*sin(25.8) = 28.......
A circular coil of wire with 38 turns and a radius of 32.1 cm is laying flat on a horizontal table as shown in the figure. There is a uniform magnetic field extending over the entire table with a magnitude of 5.37 T and directed to the north and downward, making an angle of 25.8° with the horizontal. What is the magnitude of the magnetic flux through the coil?

http://img251.imageshack.us/i/p022figure.png/

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The flux is NBA*sin(25.8) = 38*5.37*π*0.321^2*sin(25.8) = 28.7 T-m^2
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