Blackbody radiation from a star has a peak wavelength of 500nm. What is the surface temperature of the star
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Blackbody radiation from a star has a peak wavelength of 500nm. What is the surface temperature of the star

[From: ] [author: ] [Date: 11-04-24] [Hit: ]
λmax is the peak wavelength, in this case 500x10^-9m, and b is the Wien constant which is approximately 2.897x10^-3mK.Put in the values into the formula and it will give you the answer in K.Hope this helps!......
Please help explain the formula and all of the steps involved in getting the answer.

Answer is in K

Thanks!

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You can use Wien's displacement law to find out the temperature.

λmax=b/T

Rearrange it to get T= b/λmax

λmax is the peak wavelength, in this case 500x10^-9m, and b is the Wien constant which is approximately 2.897x10^-3mK.

Put in the values into the formula and it will give you the answer in K.

Hope this helps!
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