An electron moves at a speed of 7.53 m/s as it passes through a 0.60T magnetic field. Find the radius of the

An electron moves at a speed of 7.53 m/s as it passes through a 0.60T magnetic field. Find the radius of the circular path.
(me = 9.1 * 10^-31 kg, qe = 1.6 * 10^-19 c)

F=Bqv ( force in magnetic field)
F=m(v^2)/r (Centripetal force in Circular motion)
Therefore Bqv=m(v^2)/r
Bq=mv/r
r=(mv)/(Bq)
F=Centripetal force, B=Magnetic flux density(0.60T), q=Charge(1.6*10^-19C), v=Velocity(7.53 m/s),m=mass(me=9.1*10^-31Kg),r=radius of circular path(to be found).

Calculation;

r=(mv)/(Bq)
=(9.1*10^-31 * 7.53) / (0.60 * 1.6*10^-19)
=7.138*10^-11 m

Therefore the radius of the circular path is 7.138*10^-11 metres.

Hope this helps! :-)