I AM HAVING A VERY HARD TIME AND CANT UNDERSTAND ANYTHING ABOUT THIS PHYSICS QUESTION PLEASE HELP!!!!

To solve this problem, use Conservation of momentum, projectile motion, kinematics equations and conservation of energy.
initial direction of blue car (S)
initial direction of red car (S30E)
direction of entangled cars (S15E)
length of final skid 18m
Coefficient of asphalt/rubber
wet- 0.95
dry- 1.07
displacement of blue driver from collision 8m
height of blue car driver above ground when thrown horizontally 0.50m
Q............Calculate the velocity of both vehicles just after the crash when they lock together.
Q............Calculate the velocity of the driver of the blue car just before the crash.
Q............Calculate the final momentum of the system just after the crash.
Q............Calculate the momentum of each individual vehicle before the crash.
Q............Calculate the velocity of both vehicles just before the crash.
Q............Calculate the kinetic energy lost during the collision.

Please note that the initial velocities of the cars aren't known .
Thank you in advance for anybody who helps!

First notice that the two entangled cars moved away along the bisector of the 30 degree difference angle between their two initial paths. This means that the two components of linear momentum from before the crash and perpendicular to the line of the departing direction had to be equal in magnitude but opposite in direction. This let them cancel to zero perpendicular to the travel after the

crash.
Mb*Vb*sin(15 deg) = Mr*Vr*sin(15 deg); where the r and b are

subscripts referring to "red" and "blue" of the cars. The equation

is for just the magnitudes of the two momentum components.

From this: Mr*Vr = Mb*Vb. These speeds are those of the cars before the crash.
Let total mass be M = (Ma + Mb) of the entangled cars after the

crash.
The frictional force F = 1.07*W; where W is the weight-force of M.