A 603 kg satellite is in a circular orbit about the Earth at a height above the Earth equal to the Earth's

A 603 kg satellite is in a circular orbit about the Earth at a height above the Earth equal to the Earth's mean radius.


(a) Find the satellite's orbital speed.
_____m/s

(b) Find the period of its revolution
_____h

(c) Find the gravitational force acting on it.
______N

I found both answers for part a and b.
(a) i got 5580m/s and it was correct
(b) i got 4h and it was correct as well
(c) ???? SOMEONE PLEASE HELP ME FIND C

The satellite is at distance 2R from the center of Earth, hence the force of gravity is 1/4 of that acting on the surface of Earth.

Answer:
Force = 1/4 mg = 1480 Newton