By what length does a .5 mile steel iron rail stretch if its temperature were to go from -40 degrees Fahrenheit to 100 degrees Fahrenheit?
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stretch is not the word, expand is.
∆L/L = α∆T, α is linear thermal expansion coef
linear thermal expansion coef Fe 11.8e-6 /K
0.5 mile is 805 meters
140F = (5/9)140 = 78C
using iron,
∆L = Lα∆T = (805)(11.8e-6)(78) = 0.726 meter or 73 cm.
.
∆L/L = α∆T, α is linear thermal expansion coef
linear thermal expansion coef Fe 11.8e-6 /K
0.5 mile is 805 meters
140F = (5/9)140 = 78C
using iron,
∆L = Lα∆T = (805)(11.8e-6)(78) = 0.726 meter or 73 cm.
.