A mass oscillates on a spring with a period T and an amplitude 0.48 {\rm cm}. The mass is at the equilibrium p
HOME > Physics > A mass oscillates on a spring with a period T and an amplitude 0.48 {\rm cm}. The mass is at the equilibrium p

# A mass oscillates on a spring with a period T and an amplitude 0.48 {\rm cm}. The mass is at the equilibrium p

[From: ] [author: ] [Date: 11-04-23] [Hit: ]
x = 0.48cos(π) = -0.......
A mass oscillates on a spring with a period T and an amplitude 0.48 cm. The mass is at the equilibrium position x = 0 at t = 0, and is moving in the positive direction.

Where is the mass at the time t = 3T/4?

-
Given T=T, A=0.48cm
φ = -π/2 since x=0@t=0
ω = 2π/T

The position of SHM is given by:
x(t) = Acos(ωt+φ)
x(3T/4) = 0.48cos((2π/T)(3T/4)+(-π/2))
x = 0.48cos(π) = -0.48
1
keywords: the,period,mass,with,is,cm,and,spring,The,amplitude,on,an,0.48,at,equilibrium,rm,oscillates,A mass oscillates on a spring with a period T and an amplitude 0.48 {\rm cm}. The mass is at the equilibrium p
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .