A car tire makes contact with the ground on a rectangular area of 12 cm by 18 cm. The car's mass is 1060 kg. What pressure does the car exert on the ground?
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Pressure is Force/Area.
The force the car is exerting is F = m*a = m*g with the gravitational acceleration of 9.81 (in Holland at least).
The area will be the amount of tires (4?) * 0.12*0.18 meters.
The pressure will be F/Area = 1060*9.81/(4*0.12*0.18) = 120354 Pascals (N/m^2)
Or per tire: 3.01*10^4 Pascal
The force the car is exerting is F = m*a = m*g with the gravitational acceleration of 9.81 (in Holland at least).
The area will be the amount of tires (4?) * 0.12*0.18 meters.
The pressure will be F/Area = 1060*9.81/(4*0.12*0.18) = 120354 Pascals (N/m^2)
Or per tire: 3.01*10^4 Pascal
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Pressure is measured in newtons per square meter. First solve for area of contact on the ground.
Area of tire x four tires
(0.12m x 0.18m) x 4 = surface area.
surface area = 0.0864
Then solve for the cars weight in newtons. (w = mg)
1060 x 9.81 = 10,398.6N
Pressure is newtons per meter, so dissolve force by surface area.
10,398.6/0.0864 = 120,354.167N/m^2 or 120,000N/m^2 in significant figures
Area of tire x four tires
(0.12m x 0.18m) x 4 = surface area.
surface area = 0.0864
Then solve for the cars weight in newtons. (w = mg)
1060 x 9.81 = 10,398.6N
Pressure is newtons per meter, so dissolve force by surface area.
10,398.6/0.0864 = 120,354.167N/m^2 or 120,000N/m^2 in significant figures
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P = F/A
F = m*g/4 = 2597 N
A = .18*.12 = .0216 m²
P = 2597/.0216 = 120231 Pa
F = m*g/4 = 2597 N
A = .18*.12 = .0216 m²
P = 2597/.0216 = 120231 Pa