I'm out of town and haven't been in class at all for this unit. I've been trying to read online resources to help me do my homework that's due online tonight, but I'm not completely clear. Please explain in steps how you got to the answer. Your help is appreciated GREATLY. Thanks so much everyone is advance!
A series combination of two resistors, 8.05 ohm and 4.81 ohm, is connected to a 6.00 V battery.
a) Calculate the equivalent resistance of the circuit. Answer in units of ohms.
b) Calculate the current in the circuit. Answer in units of A.
c) What is the potential difference across the 8.05 ohm resistor? Answer in units of V.
d) What is the potential difference across the 4.81 ohm resistor? Answer in units of V.
A series combination of two resistors, 8.05 ohm and 4.81 ohm, is connected to a 6.00 V battery.
a) Calculate the equivalent resistance of the circuit. Answer in units of ohms.
b) Calculate the current in the circuit. Answer in units of A.
c) What is the potential difference across the 8.05 ohm resistor? Answer in units of V.
d) What is the potential difference across the 4.81 ohm resistor? Answer in units of V.
-
Equivalent resistance for series connection = sum of all individual resistances
(a) Rt = 8.05 + 4.81 = 12.86 Ohms (Ω)
(b) current = voltage (pd) / resistance = 6.0V / 12.86Ω = 0.47 Amp.
(c) voltage = current x resistance ..
(current is the same through all parts of a series connected circuit, the supply voltage is shared - depending on the individual resistance values)
. for the 8.05Ω .... V = 0.47A x 8.05Ω = 3.78 V
. for the 4.81Ω .... V = 0.47A x 4.81Ω = 2.26 V
(a) Rt = 8.05 + 4.81 = 12.86 Ohms (Ω)
(b) current = voltage (pd) / resistance = 6.0V / 12.86Ω = 0.47 Amp.
(c) voltage = current x resistance ..
(current is the same through all parts of a series connected circuit, the supply voltage is shared - depending on the individual resistance values)
. for the 8.05Ω .... V = 0.47A x 8.05Ω = 3.78 V
. for the 4.81Ω .... V = 0.47A x 4.81Ω = 2.26 V