Properties of bremsstrahlung radiation

on the wikipedia article for bremsstrahlung radiation,
http://en.wikipedia.org/wiki/Bremsstrahl…
the picture looks like it shows the emission's path to be perpendicular to the path of the electron, but i can't tell if its supposed to be perpendicular or not. can anyone with a better knowledge of physics tell me?
i suppose its a very simple conservation of momentum thing, but i'm extremely tired right now and can't for the life of me set up the equation.

It is not a conservation of momentum but that of energy and the fact that an accelerated charge must produce electromagnetic radiation, taken together. A single photon may have any direction with respect to the acceleration of the electron. However there is specific angular distribution that means there is probability distribution of photon going in different directions. Normally we may think that when a charged particle loses kinetic energy while traveling in a medium it may heat up the medium in which it is traveling but there is one more mode of emitting radiation which it follows for loss of energy. Similarly when it is accelerated by some external energy source we may think that all the energy would go into change of kinetic energy of the charged particle. But it is not so because part of this gain the charged particle will emit as e m radiation. Bremsstrahlung radiation term is used for stopping of charged particles in a medium mostly. But the physics of the process is same even, mathematically whether the charged particle is accelerated or decelerated by whatever means!