Physics 12 - Current and voltage in circuit (Diagram given)

Diagram:
http://i54.tinypic.com/3486jgy.jpg

a) What current is drawn from the battery?
b) What is the current in the 50 ohms resistor?
c) What is the voltage across the 22 ohms resistor?

Answers:
a) 1.0A
b) 013 A
c) 7.3V


For a) I tried V = IR, giving me 1.0A...I think that's the right way of doing it?
And for b) and c) V=IR doesn't seem to work anymore.

Anyone know how to do this?
Thanks!

(a) 250Ω & 50Ω are in series=>R(net) = 300Ω
Than 300Ω & 75Ω are in parallel=>R(net) = 60
30Ω & 45Ω are in parallel=>R(net) = 18Ω
Than 18Ω & 22Ω & 80Ω are in series=>R(net) = 120Ω
Now 60Ω & 120Ω are in parallel=>R(net) = 40Ω
Than 40Ω & 10Ω are in series=>Totral R(net) = 50Ω
=>By V = i x R
=>i = V/R = 50/50 = 1 amp
(b) Voltage across 40Ω = 40 volt
=>By V = iR
=>i = V/R = 40/300 = 0.13 amp
(c) By V = ix R
=>40 = i x 120
=>i = 40/120 = 0.33 amp
=>By V = iR
=>V = 0.33 x 22 = 7.26 volt