A bicycle with 0.87-m-diameter tires is coasting on a level road at 5.91 m/s. A small blue dot has been painted on the tread of the rear tire.
What is the angular speed of the tires?
What is the speed of the blue dot when it is 0.87 m above the road?
What is the speed of the blue dot when it is 0.435 m above the road?
Thank you so much!
What is the angular speed of the tires?
What is the speed of the blue dot when it is 0.87 m above the road?
What is the speed of the blue dot when it is 0.435 m above the road?
Thank you so much!
-
Circumference = Pi x 0.87, rotations per second = 5.91/(Pi x 0.87)
Angular speed = 2 x Pi x 5.91/(Pi x 0.87) = 13.6 radian/sec
Speed at 0.87m above the road = 13.6 x 0.87 = 11.8 m/s
Speed at 0.435 m above the road =sqrt(2 x (13.6 x 0.435)^2)= 8.37 m/s
Angular speed = 2 x Pi x 5.91/(Pi x 0.87) = 13.6 radian/sec
Speed at 0.87m above the road = 13.6 x 0.87 = 11.8 m/s
Speed at 0.435 m above the road =sqrt(2 x (13.6 x 0.435)^2)= 8.37 m/s