Ugh I just don't get this stuff. The question goes: A 1000 kg steel beam is supported by two ropes in a V shape coming off the center of the beam. The bottom of the "V" is a 60 degree angle. Each of the ropes can support 5600 N max. Do the ropes break?
I don't know what equation I'm supposed to use...
I don't know what equation I'm supposed to use...

The weight of the beam is given by:
w = mg = (1000 kg)(9.8 m/s²) = 9800 N
We'll do the rest with symmetry. Just look at half the picture since it's the same on both sides.
The ycomponents are all you really need to worry about for this. The ycomponent going upwards should be the same as the ycomponent going downward. The upward component is:
Tsin(60º) .......... I'll let you try to figure out why
But remember we're using symmetry so it'll be:
2Tsin(60º)
The downward ycomponent is the weight:
9800 N
So these have to be equal or equal the beam will fall or be pulled upward:
2Tsin(60º) = 9800 N
T = 9800 N / 2sin(60º) = 5658 N
Since 5656 N > 5600 N, yes the rope would break.
w = mg = (1000 kg)(9.8 m/s²) = 9800 N
We'll do the rest with symmetry. Just look at half the picture since it's the same on both sides.
The ycomponents are all you really need to worry about for this. The ycomponent going upwards should be the same as the ycomponent going downward. The upward component is:
Tsin(60º) .......... I'll let you try to figure out why
But remember we're using symmetry so it'll be:
2Tsin(60º)
The downward ycomponent is the weight:
9800 N
So these have to be equal or equal the beam will fall or be pulled upward:
2Tsin(60º) = 9800 N
T = 9800 N / 2sin(60º) = 5658 N
Since 5656 N > 5600 N, yes the rope would break.