Light speed question
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Light speed question

[From: ] [author: ] [Date: 11-12-14] [Hit: ]
I think the Nobel prize will be yours because you have officially found a particle that will eliminate world hunger, the energy produced from that partial or atom would be HUGE-speed addition of velocities close to cs = (u + v) / [ 1 + (vu/c²) ]s:Your speed relative to motionless observeru:Speed of train relative to motionless observerv: Your speed relative to the train-Nope.......

Entropy also decreases as an object increases its velocity. So as the object nears the speed of light then its entropy is nearly nonexistent. The concept of time is directly tied to that of entropy, so time for that object to an outside observer would seem to have slowed to nearly nothing.

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You cannot go faster than the speed of light like that, or in any other way.The energy required to surpass the speed of light with something with mass is infinite, this comes from the equation:
relativistic mass = rest mass/sqrt(1 - v^2/c^2)
So as the velocity becomes equal to c the denominator becomes zero which makes the evaluation undefined.

Time dilation also occurs to stop you crossing the cosmic speed limit, with a similar equation.

However technically speaking, one must use general relativistic equations to calculate things since the train is constantly accelerating as it is changing direction.

These effects occur because the speed of light is constant, read about the light clock thought experiment etc. or read Relativity: A Very Short Introduction or Why does E = mc^2, both of which are very good books about relativity.

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If you ignore everything we currently know about physics, than yes you are correct to assume that
Oh and Toby Clarke, what is this “particle or atom” that can travel faster than the speed of light, please let me know, I think the Nobel prize will be yours because you have officially found a particle that will eliminate world hunger, the energy produced from that partial or atom would be HUGE

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speed addition of velocities close to c

s = (u + v) / [ 1 + (vu/c²) ]

s: Your speed relative to motionless observer
u: Speed of train relative to motionless observer
v: Your speed relative to the train

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Nope. You see the relative velocity is not W = C + V > C it's actually W = (C + V)/(1 + CV/C^2)
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