What is the acceleration of a small metal sphere that falls
through water? The sphere weighs 2.8x10^-1 (ten to the negative first
power) in air and has a volume of 13 cm cubed
through water? The sphere weighs 2.8x10^-1 (ten to the negative first
power) in air and has a volume of 13 cm cubed
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13(cm)^3 = 1.3e-5 m^3
Mass of the sphere = 2.8x10^-1 kg (assumed to be)
Net force inside water = (2.8e-1 - 1.3e-5*1000)*9.8 N where 1000 is the density of water
Acceleration = force / mass = (2.8e-1 - 1.3e-5*1000)*9.8 / 2.8e-1
9.345 m/s^2
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Mass of the sphere = 2.8x10^-1 kg (assumed to be)
Net force inside water = (2.8e-1 - 1.3e-5*1000)*9.8 N where 1000 is the density of water
Acceleration = force / mass = (2.8e-1 - 1.3e-5*1000)*9.8 / 2.8e-1
9.345 m/s^2
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2.8 x 10^-1 what unit? Grams, kilograms, what? 13 cm^3 of water has a mass of about 13 grams. The force acting on the sphere is proportional to its mass minus the mass of water, and its acceleration is f/m.
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Well first off, what is its acceleration? and second you said the Sphere weighs 2.8x10^(-1), what? you left your number "Naked" is it Centermeters? Meters? Kilometers?