A fully charged capacitor stores 10.2 J of energy.
How much energy remains when its charge
has decreased to half its original value?
Answer in units of J
How much energy remains when its charge
has decreased to half its original value?
Answer in units of J
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energy of a capacitor U = Q^2 / 2 C, where Q is the charge and C is the capacitance
so that for two cases , U1 / U2 = (Q1/Q2)^2 and hence, 10.2 / U2 = ([(Q/Q/2)]^2 = 4
or U2 = final energy = 10.2 / 4 = 2.55 J.
so that for two cases , U1 / U2 = (Q1/Q2)^2 and hence, 10.2 / U2 = ([(Q/Q/2)]^2 = 4
or U2 = final energy = 10.2 / 4 = 2.55 J.
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The answer is
10.2/2=5.1 J
Since its half the original value you simply divide by 2
10.2/2=5.1 J
Since its half the original value you simply divide by 2
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