A test tube in a centrifuge is pivoted so that it swings out horizontally as the machine builds up speed. If t
[From: ] [author: ] [Date: 12-03-17] [Hit: ]
and if the machine hits 54000 revolutions per minute, what would be the centripetal force exerted on a giant amoeba of mass 1.0 multiplied by 10 ^ -8 kg at the bottom of the tube?-F = m R ω ² = 1.e-8*0.136 *(2*π*54000/60) ² = 0.......
A test tube in a centrifuge is pivoted so that it swings out horizontally as the machine builds up speed. If the bottom of the tube is 136 mm from the central spin axis, and if the machine hits 54000 revolutions per minute, what would be the centripetal force exerted on a giant amoeba of mass 1.0 multiplied by 10 ^ -8 kg at the bottom of the tube?
-
F = m R ω ² = 1.e-8*0.136 *(2*π*54000/60) ² = 0.044 N
----------------------------
1
keywords: the,centrifuge,pivoted,is,horizontally,swings,as,tube,out,machine,it,speed,test,so,builds,in,If,up,that,A test tube in a centrifuge is pivoted so that it swings out horizontally as the machine builds up speed. If t
