Please look at this diagram
http://flic.kr/p/bGxpFk
In the diagram, you will see the setup is different from normal. There is an angle 60 degrees where the light cord starts.
The box's true weight is 10N. What would the tension on the left side be?
is it just 10N? or do I have to deal with sin and cos ?
There is actually a scale between the wall and the pulley.
The question is what force would the scale read.
(friction on pulley and weight of cords are ignored in the question)
Thank you.
http://flic.kr/p/bGxpFk
In the diagram, you will see the setup is different from normal. There is an angle 60 degrees where the light cord starts.
The box's true weight is 10N. What would the tension on the left side be?
is it just 10N? or do I have to deal with sin and cos ?
There is actually a scale between the wall and the pulley.
The question is what force would the scale read.
(friction on pulley and weight of cords are ignored in the question)
Thank you.
-
If the pulley and cord are ideal (as they seem to be), then the 10 N tension holding up the box is transmitted unchanged through the cord. Is the scale your typical spring-scale inserted into the cord between the wall and the pulley? If that's the case, then it will read 10 N.