A 2.00 kg mass is connected to a spring with a spring constant of 9.00 N/m. The velocity is given by the expression v(t) = 10.0 cm/s sin(ω t). What is the maximum acceleration of the simple harmonic motion?
A. 17.5 cm/s2
B. 21.2 cm/s2
C. 25.2 cm/s2
D. 30.5 cm/s2
E. 36.7 cm/s2
A. 17.5 cm/s2
B. 21.2 cm/s2
C. 25.2 cm/s2
D. 30.5 cm/s2
E. 36.7 cm/s2
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w = √[k/m] = 2.121 rad/sec
vmax = wA = 10 → A = 4.715 cm
amax = w²*A = 21.2 cm/s²
vmax = wA = 10 → A = 4.715 cm
amax = w²*A = 21.2 cm/s²