Uncharged capacitor in a simple circuit
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Uncharged capacitor in a simple circuit

[From: ] [author: ] [Date: 12-04-09] [Hit: ]
then if V-Vc> voltage required for the bulb to glow ,it will glow.But as the charging continues the voltage Vc gets nearer to V and at some point the bulb will stop glowing.Generally it may glow few seconds depending upon the time constant of the circuit.......
Hey everyone, I'm still a little confused on capacitors.

The question I'm looking at is a straightforward circuit, containing a battery followed by a switch, lightbulb, and then capacitor. The capacitor is initially uncharged, and the question asks about the light bulb after the switch becomes closed.

My understanding is that current would flow to the capacitor until it was fully charged. The lightbulb would light up as soon as the switch was closed, and then would grow dimmer as the capacitor charged until the capacitor was full. At that point, the light would go out. Is that how it would work?


Thanks.

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yeah you are right.!
the thing is as the capacitor gets charged it builds up voltage that opposes the supply voltage,i mean the voltage across the capacitor is actually the drop. V=supply
Vc=voltage at an instant across the capacitor
then if V-Vc> voltage required for the bulb to glow ,it will glow.But as the charging continues the voltage Vc gets nearer to V and at some point the bulb will stop glowing.Generally it may glow few seconds depending upon the time constant of the circuit.
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