3 + 4x − 2x^2 = a(x + h)^2 + k

The value of A, H, and K = ?

I have no idea where to start... any help is much appreciated

Thanks for your time.

3 + 4x − 2x^2 = a(x + h)^2 + k

a(x + h)^2 + k = 3 + 4x − 2x^2

a(x + h)^2 + k = -2x^2 + 4x+3

a(x + h)^2 + k = -2(x^2 - 2x ) +3

a(x + h)^2 + k = -2 (x^2 - 2x + 1) + 3 +2

a(x + h)^2 + k = - 2(x - 1)^2 + 5

A = -2
H = -1
K=5