Yet another physics question! In this question, an object is thrown straight up into the air. I am given an initial velocity (m/s) and acceleration due to gravity (9.81 m/s squared). I have to determine what height the object rises to.
How do I determine the height to which the object rises with these givens? Please provide an equation and explanation. T'would be very much appreciated!
How do I determine the height to which the object rises with these givens? Please provide an equation and explanation. T'would be very much appreciated!
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The basic equation for kinematics is y = 1/2 * a * t^2 + v_o * t + y_o
Which, using a derivative, can turn into v = a*t + v_o
a is acceleration, v_o is initial velocity, and y_o is initial height in the first equation, v_o is initial velocity in the second equation.
You know when an object is at its highest point it will have zero velocity because it is turning around from going up to going down. Use the second equation to solve for what time your object will hit this point. Then use the first equation, since you now know what time the object reaches the highest point.
Which, using a derivative, can turn into v = a*t + v_o
a is acceleration, v_o is initial velocity, and y_o is initial height in the first equation, v_o is initial velocity in the second equation.
You know when an object is at its highest point it will have zero velocity because it is turning around from going up to going down. Use the second equation to solve for what time your object will hit this point. Then use the first equation, since you now know what time the object reaches the highest point.