What is the radius of the path of an electron accelerated by voltage 5.0 KV
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What is the radius of the path of an electron accelerated by voltage 5.0 KV

[From: ] [author: ] [Date: 12-06-01] [Hit: ]
The answer I got when I substituted mass of electron for m, voltage for V, charge of electron for q and field strength for B was r=4.0x10^-3m. My instructor says this is wrong though and I have no idea where Im making a mistake since Ive checked it a bunch of times.-The B should not be under the square root.......
I'm confident I have the method for solving this right. I used the formula for kinetic energy and voltage (1/2mv^2=qV) and combined it with my modified magnetic force formula (r=mv/qB) to get:
r=sqrt of ((2mV/q)/B)
The strength of B is 3.0x10^3 in Tesla.
The answer I got when I substituted mass of electron for m, voltage for V, charge of electron for q and field strength for B was r=4.0x10^-3m. My instructor says this is wrong though and I have no idea where I'm making a mistake since I've checked it a bunch of times.

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The "B" should not be under the square root.
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