Banking angle coefficient of friction problem
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Banking angle coefficient of friction problem

[From: ] [author: ] [Date: 12-06-18] [Hit: ]
4 + µcos27.4)}/{cos27.4 - µsin27.=>625{0.89 - 0.46µ} = {247.......
A car on a curved race track (with radius = 55 m) is banked at an angle of 27.4 degrees. The car is traveling 25 m/s and mass of the car is not given. What should the coefficient of friction (max), μs be for the car to not skid?

What I'm trying to figure out is how to solve for the coefficient of friction without knowing mass and natural force of the car. Components of natural force are:
Fn Cos 27.4 for y and Fn Sin 27.4 for x

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By v = √[{rg(sinθ + µcosθ)}/{cosθ - µsinθ}]
=>(25)^2 = {55 x 9.8(sin27.4 + µcos27.4)}/{cos27.4 - µsin27.4}
=>625{0.89 - 0.46µ} = {247.94 + 479.71µ}
=>767.21µ = 308.31
=>µ = 0.40
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keywords: coefficient,problem,Banking,friction,angle,of,Banking angle coefficient of friction problem
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