Finding the depth given the pressure only
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Finding the depth given the pressure only

[From: ] [author: ] [Date: 12-06-25] [Hit: ]
Essentially you have a column of seawater , volume (v) of height (h) acting over an area (a) of 1 sq m which has a weight of 100,000 newtons.So pressure p = weight / area = ( (v * d * g) / a ) , so : v = ( (p * a) / (d * g) ) = 9.So,......
This is the question that i found in the book:

At what depth in seawater is the gauge pressure 1.00 x 10^5 Pa?

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100,000 Pa = 100,000 newtons / sq m
You need the density (d) of seawater, ive used 1020 kg / cu m
Acceleration due to gravity (g) = 9.81 (m/s)/s

Essentially you have a column of seawater , volume (v) of height (h) acting over an area (a) of 1 sq m which has a weight of 100,000 newtons.
So pressure p = weight / area = ( (v * d * g) / a ) , so : v = ( (p * a) / (d * g) ) = 9.994 cu m
So, you have a cylinder of seawater, volume 9.994 cu m, with a (cross sectional) area of 1 sq m
So if volume (of a cylinder) = area * height , then height = volume / area = 9.994 / 1 = 9.994 metres
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