A rock is thrown downward from an unknown height above the ground with an initial speed of 27 m/s. It strikes the ground 7.2 s later.
Determine the initial height of the rock above the ground.
Determine the initial height of the rock above the ground.
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h = 1/2 g t^2 + Vo t
= 1/2 x 9.8 x 7.2^2 + 27 x 7.2
= 254.016 + 194.4
= 448.416 m
= 1/2 x 9.8 x 7.2^2 + 27 x 7.2
= 254.016 + 194.4
= 448.416 m