You spray your sister with water from a garden hose. The water is supplied to the hose at a rate of .111 liters per second and the diameter of the nozzle you hold is 5.23 mm. At what speed does the water exit the nozzle?
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By Q = Av
=>0.111 x 10^-3 = (1/4 x π x d^2) x v {as 1 Lt. = 10^-3 m^3}
=11.10 x 10^-5 = 0.25 x 3.14 x (5.23 x 10^-3)^2 x v
=>v = 5.17 m/s
=>0.111 x 10^-3 = (1/4 x π x d^2) x v {as 1 Lt. = 10^-3 m^3}
=11.10 x 10^-5 = 0.25 x 3.14 x (5.23 x 10^-3)^2 x v
=>v = 5.17 m/s
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Flow rate = velocity x area of nozzle = 0.111 l/ s Solve for velocity
area = Pi x r^2 r = 5.23/2 mm = 0.00523/2 m/s
area = Pi x r^2 r = 5.23/2 mm = 0.00523/2 m/s