A car accelerates uniformly from rest for half a minute with an acceleration of 1.2 m/s2. It then travels at

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A car accelerates uniformly from rest for half a minute with an acceleration of 1.2 m/s2. It then travels at

[From: ] [author: ] [Date: 13-03-03] [Hit: ]

Total distance = 540 m + 3,240m + 360 m = 4,......

a constant speed for 1.5 minutes before slowing down with a uniform acceleration to come to rest in 20 seconds. Calculate the total distance covered by the car..

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1/2 at^2 = 540 m - 1st leg

at ( velocity at the end of 30 secs) x 90 sec = 36 m/s x 90 sec = 3,240 m - 2nd leg

(u + v)/2 x t =( 36 m/s + 0 )/2 x 20 sec = 360 m - 3rd leg

Total distance = 540 m + 3,240m + 360 m = 4,140 m

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