What would be the average density of a black hole with the radius of our universe
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What would be the average density of a black hole with the radius of our universe

[From: ] [author: ] [Date: 11-11-26] [Hit: ]
You could also modify your question as, what is the average density, or what is the mass contained within a Scharzschild radius (Rs) equal to the radius of the universe.solving for mass:m = (Rs)c^2 / 2G.Where G is gravitational constant (6.673 x 10^11 m^3/kg-s^2) and c is speed of light (3 x 10^8 m/s).......
A black hole has essentially infinite density, which means it has no volume, so this question seems to be a conundrum. The mass of the known (observable) universe, depending on which source you use, is about 3 x 10^54 kg. You could also modify your question as, what is the average density, or what is the mass contained within a Scharzschild radius (Rs) equal to the radius of the universe.

Rs = 2Gm / c^2;
solving for mass: m = (Rs)c^2 / 2G.

Where G is gravitational constant (6.673 x 10^11 m^3/kg-s^2) and c is speed of light (3 x 10^8 m/s).

When you crank this out for the radius of the universe, you realize that the radius of the observable universe (4 x 10^26 m), based on it's calculated mass, is approximately at its Scharzschild radius. This lent to the question, years ago, whether the universe would continue its inflation or after the current expansion, which was thought to be entirely from the inertia of the big bang, would gradually slow it's rate and then start contracting and condense into a singularity, a black hole with the mass of the universe. Now we have observed what seems like an acceleration of the rate of inflation of the universe so, assuming that this acceleration is not just a characteristic of our region of the universe and is true everywhere, it is presumed there are other mysterious forces at work.

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The radius of the visible universe is about 4.32 × 10^26 meters (14.0 billion parsecs). A black hole (non-rotating) with an event horizon of that size would have a mass of 2.91 x 10^53 kg. The concept of "volume" for a black hole is weird; you can't use the normal formula (4/3) pi r^3. Instead, the volume would be 1.72 x 10^100 m^3, for a density of 1.69 x 10^-46 kg/m^3.

Using a "volume" without considering general relativity, the density is 0.86 x 10^-27 kg/m^3

The density of the universe today is about 9 x 10^-27 kg/m^3, or maybe half or twice this.

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i,d love to answer but i hate black colour.
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