Help with Hardy-Weinberg! Already did the work, just need someone to check.

Sorry there is so much. I already answered them i just need someone to check. Thanks so much.

In a population of red (dominant) and white flowers, the frequency of red flowers is 91%. What is the frequency of the red allele?

30%
70%
9%
91%
Isn't it just 91%? is this a trick question?

Red short-horned cattle are homozygous for the red allele, white cattle are homozygous for the white allele, and roan cattle are heterozygotes. Population A consists of 36% red, 16% white, and 48% roan cattle. What are the allele frequencies?

red = 0.36, white = 0.16
red = 0.6, white = 0.4
red = 0.84, white = 0.16
red = 0.5, white = 0.5
Allele frequencies cannot be determined unless the population is in equilibrium.
I said red is .6 and white is .4.

If, on average, 46% of the loci in a species' gene pool are heterozygous, then the average homozygosity of the species should be

23%
46%
54%
92%
There is not enough information to say.
I said d, not enough info.

1) Red flower (R-) = 91%
white flower (rr) = 9%
freq of white allele, q(r) = SQRT 0.09 = 0.3
freq of red allele, p(R) = 1 - 0.3 = 0.7 or 70%

2)
freq of red allele, p(R) = 0.36 + 1/2(0.48) = 0.6
freq of white allele q(W) = 0.16 + 1/2(0.48) = 0.4
So, your answer is correct.

3)
54%
It consists of recessive homozygote (aa) and dominant homozygote (AA).

The frequency is not in percent. So for red allele it should be .7. The choices does not make any sense.

yup you are right. It is .6 and .4

I think so too.