How to calculate molarity for this problem

1.6 L solution containing 1.55 g of dissolved KBr. The molar mass is 119.0 g/mole? I'm confused about this problem

Molarity=mol of solute/L of solution or sumthin like that . But you convert g to mol for the 1.55 g of KBr . Then you divide it by 1.6 L .
This is what it would look like :
1.55g/x=119/1
Where x=#of mol
X=.013mol
Mol of solute=.013
L of solution=1.6
.013/1.6
Then u get ur answer !