In the following equation, identify the acid and base on the reactants side as well as their conjugates on the
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In the following equation, identify the acid and base on the reactants side as well as their conjugates on the

[From: ] [author: ] [Date: 11-05-24] [Hit: ]
PLEASE HELP ITS FOR HOMEWORK!!!1.They can be found on opposite sides of the equation.2.......
In the following equation, identify the acid and base on the reactants side as well as their conjugates on the products side.

H2O + H2O ↔ H3O+ + OH-
PLEASE HELP ITS FOR HOMEWORK!!!

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An acid-base conjugate pair can be identified in the following way:
1. They can be found on opposite sides of the equation.
2. Their formulas are very similar, except that the "acid" has one more hydrogen than its "conjugate base"
In the above equation, there are two conjugate acid-base pairs.
The first one is H2O and H3O^+, where H2O is the base that gains a proton (H^+) and becomes its conjugate acid H3O^+.
The second one is H2O and OH^-, where H2O is the acid that loses a proton and becomes its conjugate base OH^-.
In this reaction H2O acts as both an acid (proton donor) and a base (proton acceptor.

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On the left, you can identify either one as acid or base. It's the same compound really.

H3O (hydronium) is willing to donate a proton (which is an H+ ion due to the autodisasociation of water) and is therefore an acid.

OH- (hydroxide) on the other hand is willing to accept a proton, which makes it a base.

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H2O act as both acid and base, so take any one of the H20 in reactant side and other the base wheareas in the product side, H30 is acid and OH being base..

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H20 is the base and H3O is its conjugate acid. H20 is the acids and OH- is its conjugate base.
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