How many grams of Ca(OH)2 are needed to neutralize 5 g of 3-methylbutanoic acid

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How many grams of Ca(OH)2 are needed to neutralize 5 g of 3-methylbutanoic acid

[From: ] [author: ] [Date: 11-06-27] [Hit: ]

The formula for 3-methylbutanoic acid is C5H10O2.The molecular mass of 3-methylbutanoic acid is 102.1317 g/mol.(5 gC5H10O2) / (102.1317 g C5H10O2/mol) x (1/2) x (74.1.......

a- 1.81 g
b- 3.68g
c- 2.10g
d- 4.20g

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3-methylbutanoic acid has one carboxyl group, so each mole of Ca(OH)2 will neutralize two moles of 3-methylbutanoic acid.

The formula for 3-methylbutanoic acid is C5H10O2.
The molecular mass of 3-methylbutanoic acid is 102.1317 g/mol.

(5 g C5H10O2) / (102.1317 g C5H10O2/mol) x (1/2) x (74.0932 g Ca(OH)2/mol) =
1.8 g Ca(OH)2

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