A 3920N is traveling at 8m/s. The drivers slams on the breaks and brings the car to a rest....(force question)

1. A 3920N is traveling at 8m/s. The drivers slams on the breaks and brings the car to a rest in a distance of 10 meters.

a. What is the net acceleration of the vehicle?
b. What is the net force acting on the object?
c. What is the friction coefficient between the vehicle and the road?

Also could you explain a little bit more about what net acceleration and net force. Thanks!

I guess the 3290N. is a car, and the "object" in B is the same car. But cars have BRAKES, hopefully not breaks.
a) Acceleration = (v^2/2d), = 3.2m/sec^2. negative.
b) Net force acting on car when braking = (ma) = (3,290/9.8) x 3.2, = 1,074.286N.
Frictional coefficient = (1,074.286/3,290) = 0.3265.

a. a = -(V²)/(2x) = -8²/(2*10) = -3.2 m/sec²

b. F = m*a = (W/g)*a = (3920/9.8)*(-3.2) = -1280 N

c. µ ≥ a/g = 3.2/9.8 = .326