Calculate the molarity of a solution consisting of 60.0g of NaOH is l.50 L of solution
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Calculate the molarity of a solution consisting of 60.0g of NaOH is l.50 L of solution

[From: ] [author: ] [Date: 11-09-22] [Hit: ]
we need to know how many moles of NaOH we actually have, and this is given by mol=mass/mr.The Mr of NaOH is 40, so we have 60.0/40 mol = 1.5mol.......
How do you do this? Steps cause other wise i can't do the other examples i have! 10 points!

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Okay, we need to know how many moles of NaOH we actually have, and this is given by mol=mass/mr.
The Mr of NaOH is 40, so we have 60.0/40 mol = 1.5mol. 1.5L is the same as 1.5dm^3. We have 1.5moles in this volume of solution, so we do 1.5mol/1.5dm^3 = 1mol/dm^3, read as 1 mole per decimetre cubed. This is 1M.

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concentration = moles/volume
moles = mass/molar mass = 60.0/(23 +16 +1) = 1.5 moles of sodium hydroxide
concentration = moles/volume = 1.5/1.5 = 1.0 moles per liter = molarity of 1.0
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